Language Theory: Interpreting the Regular Expression (a∣b)∗(a \mid b)^*

Language Theory: Interpreting the Regular Expression (a∣b)∗(a \mid b)^*

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Nov 4, 2026

The regular expression (a∣b)∗(a \mid b)^* uses two core operations: union (a∣b)(a \mid b) and Kleene star ∗{}^*. Intuitively, (a∣b)(a \mid b) means “choose either aa or bb as the next symbol,” and ∗{}^* means “repeat that choice any number of times, including zero repetitions.” Therefore, (a∣b)∗(a \mid b)^* denotes the language of all finite strings over the alphabet {a,b}\{a,b\}, including the empty string ε\varepsilon.

A precise way to see this is: (a∣b)∗(a \mid b)^* is the set of strings that can be written as concatenations of zero or more symbols, where each symbol is either aa or bb—hence every string over {a,b}\{a,b\} is included, and ε\varepsilon is included because zero repetitions is allowed.

We can express the option mapping directly:

  • (i) “Strings containing only aa” — only a subset of the language.
  • (ii) “Strings containing only bb” — only a subset of the language.
  • (iii) “All strings over {a,b}\{a,b\}, including ε\varepsilon” — exactly the language.
  • (iv) “Strings beginning with abab” — only a subset (and does not include many strings that don’t begin with abab like ε\varepsilon, aa, bb, baba, etc.).

Below is a structured breakdown of why.

Key terms you’ll use:

  • KleeneStar
  • Union
  • RegularLanguage
  • Epsilon
  • Alphabet

Note: In regular-expression semantics, E∗E^* always includes ε\varepsilon (zero repetitions). That single fact already rules out option (iv) and confirms option (iii).

Evaluate what $(a \mid b)^*$ generates

  1. 1
    Step 1

    A string generated by (a∣b)(a \mid b) of length 1 can be either

  2. 2
    Step 2

    The star allows concatenating 0,1,2,... repetitions of (a∣b)(a \mid b).

  3. 3
    Step 3

    With 0 repetitions, the generated string is 0˘3b5\u03b5.

  4. 4
    Step 4

    With n≥1n\ge 1 repetitions, each position can be aa or bb, so every length-nn string over {a,b}\{a,b\} is included.

  5. 5
    Step 5

    Thus the language is all strings over {a,b}\{a,b\} including 0˘3b5\u03b5, which corresponds to option (iii).

Fast mental check

Because (a∣b)∗(a \mid b)^* includes ε\varepsilon, any option that requires a specific prefix like “beginning with abab” cannot be correct.

Common misconception

“∗^*” does not mean “exactly one occurrence” or “must contain a particular substring.” It means “any number of repetitions, including zero.”

How each option compares to the language of (a∣b)∗(a|b)^*

All strings over {a,b} is the full set; each option represents a subset (or mismatch).

Option-by-option justification

Regular-expression reading workflow

Read union

1

Identify what each position can be: aa or bb."

Apply star

2

Allow zero or more repetitions of the union."

Check for ε

3

Star implies 0˘3b5\u03b5 is always in the language."

Match to options

4

Compare required prefixes/substrings vs what repetition actually allows."

Knowledge Check

Question 1 of 4
Q1Single choice

What language does (a∣b)∗(a\mid b)^* represent?